Re: cannot assign result of a template with block argument unless surrounded by a block expression

[evacchi]

that is correct. yet
    
    
    template foo(p: untyped): auto = (block:
          1
    )
    
    let x = foo:
      discard
    

won't compile, while this will
    
    
    let x = (block:
      1
    )
    

in fact, this compiles as well:
    
    
    
    template foo(p: untyped): auto = (block:
          1
    )
    
    let x = foo(3)
    

that's why I feel like it might a parsing problem (it doesn't compile only when 
the arg is a block)