When a proc call a macro with typedesc parameter, we can just user the type
name, but when we call another macro in the macro and pass the typedesc
parameter to it, something is strange, look at the code:
type
User = object
id: int
name: string
age: int
macro stepTwo(T: typedesc): untyped =
echo "In step 2: "
echo repr T.getType()
macro m2(T: typedesc): untyped =
let nT = quote do: `T` #Sym "User"
let t1 = T.getType()[1] #Sym "User"
let t2 = bindSym"User" #Sym "User"
echo t1 == nT # true
echo t1 == t2 # true
echo t2 == nT # true
#result = newCall("stepTwo", t1) # ERROR!!
#result = newCall("stepTwo", t2) # ERROR!!
result = newCall("stepTwo", nT) # OK!
m2(User)
How can I pass the User as typedesc paramter to the macro stepTwo if there is
no 'T' parameter? Why the t1, t2 cannot be treated as correct typedesc, they
all Sym "User" just like nT.
Help needed, thanks.
