Re: Function as object? Object as function?

[mjendrusch]

You can get this behaviour by overloading the experimental () operator on an 
object type, like so:
    
    
    {. experimental .}
    
    import math
    
    type
      Callable = object
        val: int
    
    # Make the thing callable. Needs {. experimental .}
    proc `()`(c: Callable; i: int): int = c.val * i
    
    # Make the thing exponentiable.
    proc `^`(c: Callable; i: int): int = c.val ^ i
    
    let c = Callable(val: 1)
    
    echo c ^ 2 == 1.c ^ 2 # true!
    

You could probably object-ify any given function to behave this way using a 
macro.