This works:
macro t2(): untyped =
result = getAst(t1())
#t2()
Run
A macro produces an abstract syntax tree (AST) of nodes, that's what is
assigned to its `result` variable. A macro call like `t1()` is replaced with
the code representation of this AST, not with the AST itself. If you need the
AST, and you do in `result = t1()` because `t2` is supposed to return an AST,
wrap it with `getAST`. Alternatively, `t1` could become a `proc`.
> Even stranger if I comment out t1 and add discard...
The compiler just warns about `t2` not being used because the call to it is
commented out, not sure what you mean.
