now I am completely confused. When there is a `ashr` (which I have never noticed), why is there the need to change the behavior of `shr` for signed `int`? I can't see the point.
- rant about shr change adrianv
- Re: rant about shr change lscrd
- Re: rant about shr change Stefan_Salewski
- Re: rant about shr change lscrd
- Re: rant about shr change Araq
- Re: rant about shr change adrianv
- Re: rant about shr change Araq
- Re: rant about shr change adrianv
- Re: rant about shr change Araq
- Re: rant about shr change GordonBGood