Thank you very Mratsim! That worked. It seems like the function is returning
too early - I'm assuming because result is being used in the if block? I
modified the proc to make it a bit more obvious what is happening, and when.
I'm expecting two values in the seq to be returned not one. A second question
that I have is, I'm expecting that when proc is being called in that first if
block - both with the if, and else that the rest of the proc is being foregone.
Am I thinking about this the right way?
import sequtils
let file = readfile("testing")
proc splitstring(string_to_split: string, split_by: string, acc:
seq[string]): seq[string] {.discardable.} =
let search_len = split_by.len
let found = string_to_split.find(split_by)
let end_position = found + search_len + -1
echo(end_position)
if found != -1:
echo("string was found")
let new_string_start = end_position + 1
let new_string = string_to_split[new_string_start..^1]
if len(acc) == 0:
result.add(string_to_split[0..end_position])
splitstring(new_string, split_by, result)
else:
result = acc
result.add(string_to_split[0..end_position])
splitstring(new_string,split_by, result)
else:
echo("the final result of splitting was ",acc)
result = acc
#start of main
var indi_files = splitstring(file,"</OFX>",@[])
echo("the final result returned to indi_files ",indi_files)
Run
Output
17
string was found
25
string was found
4
the final result of splitting was @["asdfasdfasdf</OFX>",
"bbbbbbbbbbbbbbbbbbbb<
/OFX>"]
the final result returned to indi_files @["asdfasdfasdf</OFX>"]
