Re: How to declare container variable for proc?

[Tim_H]

Would something like this work for you? 
    
    
    proc a(x: int): int = x+1
    proc b(x: int): int = x+2
    
    var container: proc(x:int):int
    
    if 4 > 5:
      container = a
    else:
      container = b
    
    echo $container(3)
    
    Run