Isn't there a way to tell bash not to buffer an output descriptor? I know 
you can do it with ioctl inside C/C++.

-----Original Message-----
From: [email protected] [mailto:[email protected]] On 
Behalf Of Steven S. Critchfield
Sent: Wednesday, February 19, 2014 12:02 PM
To: [email protected]
Subject: Re: [nlug] Weird CentOS 6 Bash/Grep issue

----- Original Message -----
> OK, the mystery shifts. If I don't setup the "real time" (sub-level
> child?)
> with the '-f' and just do a same level operation such as:
>
> tail -500 /var/log/pfsense | egrep -e '\.25\:' -e '\.465\:' -e
> '\.587\:' | grep -v '192\.168\.0\.71'
>
> it works as desired!
>
> Something with the child process of the tail that is continuously
> reading the target(s) and feeding them to STDOUT in real time doesn't
> like that fork to the 2nd grep. I tried encapsulating the tail in '('
> and ')' but no go.

What you are seeing is really simple. It is output buffering. Since the tail 
above sends out a block and then EOF, the first grep can filter and EOF, 
then the final grep can filter and EOF flush.

In the other, you are waiting for a buffer fill before it will start 
displaying.

--
Steven Critchfield [email protected]

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