I just use Number() [note, no `new` ctor]. No idiomatic operator soup, just
an expressive conversion. Floats are preserved.
> Number('08') === 8
true
> Number('1.2') === 1.2
true
On Tue, Feb 21, 2012 at 7:10 PM, Louis Santillan <[email protected]> wrote:
> Thomas Fuchs recommends using double tilda (~~) for string conversion.
> Safer and just as fast (
> http://mir.aculo.us/2010/05/12/adventures-in-javascript-number-parsing/).
>
> -L
>
>
> On Tuesday, February 21, 2012, Murvin Lai wrote:
>
>> proper use of parseInt is do that. parseInt(number, 10) for 10-base.
>>
>> On Tue, Feb 21, 2012 at 2:16 PM, Andrew Chilton <[email protected]>wrote:
>>
>>> On 22 February 2012 10:46, Tim Caswell <[email protected]> wrote:
>>> > While it's annoying, it's a good idea to always specify the radix (the
>>> > second argument to parseInt) when parsing numbers and you know the
>>> > radix. This is why jslint yells at you if you leave this "optional"
>>> argument
>>> > off.
>>>
>>> On a slightly different note, another good way (which Crockford also
>>> suggests) is instead of using parseInt(), coerce the string into
>>> number by using +'08'. This will give you the number 8.
>>>
>>> Note that in your case this may not be what you want since it gives a
>>> number, not an integer. This is fine if you know your string contains
>>> a round number, but not if your string can contain a decimal point.
>>> e.g. +'08.5' will give you the number 8.5.
>>>
>>> If you ever use this in a calculation of some sort, it's also good to
>>> put parens around your coerce. For example:
>>>
>>> var x = something + (+'08') + whatever;
>>>
>>> Cheers,
>>> Andy
>>>
>>> --
>>> Andrew Chilton
>>> e: [email protected]
>>> w: http://www.appsattic.com/
>>>
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