Maybe I don't get it, but how can I force Number() to give me an
Integer? parseInt('2.3') will give me an integer. Number('2.3') will
give me a float.

Once, I gave my students the task to calculate the quarter of the
year. With a type strict compiler language like C the algorithm is
pretty simple: date.getMonth() / 3 + 1.
Because they were not thinking of integers it was tough for them to
figure out the algorithm. Sometimes you just need integers.
parseInt(date.getMonth() / 3, 10) + 1.

Plus, I thought this is a discussion about parseInt().

On Feb 24, 9:47 pm, Marcel Laverdet <[email protected]> wrote:
> So? That's nothing we haven't covered here. Personally I'd recommend:
> String.prototype.toNumber = function() { return Number(this) };
>
> Actually I wouldn't recommend it, I'd recommend just using Number() or +
> without touching the prototype.
>
>
>
>
>
>
>
> On Fri, Feb 24, 2012 at 1:46 PM, Jorge <[email protected]> wrote:
> > On Feb 24, 2012, at 8:37 PM, Marcel Laverdet wrote:
>
> > > You could extend String.prototype if you wanted to but it's probably one
> > of the less common ways to do this kind of thing. It has disadvantages like
> > portability, and it will ONLY works on strings. Using Number() or + on
> > something that's not a string (undefined, an object, a number) will work
> > fine, but your prototype idea will fail. If you did want to go this way I'd
> > recommend calling it `toNumber` to match the `toString` convention.
>
> > String.prototype.toInt= function toInt () { return parseInt(this, 10) };
> > "123 px".toInt()
> > 123
> > --
> > Jorge.
>
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