Thanks mlegenhausen, that was exactly what I was looking for. It is a RPC call indeed.
Cheers, Cassio On Apr 30, 9:10 am, mlegenhausen <[email protected]> wrote: > One solution is to subscribe to the queue in your request handler: > > app.get('/test', loadUser, function(req, res) { > queue.subscribe(function(msg) { > // Unsubcribe here. Maybe there is something like a once listener? > res.send(msg.data); > }); > exchange.publish('task_queue', 'functional!', { > replyTo: 'incoming' > }); > > }); > > Don't know exactly if this is the thing you want to do? Cause this looks > more like a rpc request you want to make. Queues are more used for async > tasks where the result is returns later on and then I would prefer to use > socket.io for async response. -- Job Board: http://jobs.nodejs.org/ Posting guidelines: https://github.com/joyent/node/wiki/Mailing-List-Posting-Guidelines You received this message because you are subscribed to the Google Groups "nodejs" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/nodejs?hl=en?hl=en
