That wouldn't work because you cannot call doubleFoo.m directly without
creating a new doubleFoo objected. Secondly, even if you would instantiate
a new doubleFoo object the m function will get overriden by foo.m (since
that's stored in the prototype). Last but not least, you cannot call
this.inherited if there's no class to inherit from (a class inherits from a
super class if the uber property stores a reference to that super class).
What you can do instead is extend the foo class with its own m method and
then call inherited inside the m function:
var Cls = require('Cls');
var Foo = Cls({
methods: {
m: function (x) {
console.log(x);
}
}
});
var DoubleFoo = Cls({
uber: Foo,
methods: {
m: function(x) {
// first argument is name of super function, second is array of
arguments
this.inherited('m', [x * 2]);
}
}
});
var df = new DoubleFoo();
df.m(1);
You may be asking yourself why the heck do i ask for the name of the super
function when calling inherited?
Well, I could have just used this.inherited(arguments) or simply
this.inherited() and make the function call super with the last function
that was executed on the child, like Klass (https://github.com/ded/klass)
does.
The problem with that is that if I call functionA and functionB of the "sub
class" (the class that inherits from the super class) and function a would
call this.inherited() after 2 seconds for example that wouldn't work
(because the last function called would be functionB not functionA).
Example that wouldn't work:
var Foo = Cls({
methods: {
m: function (x) {
console.log(x);
}
}
});
var DoubleFoo = Cls({
uber: Foo,
methods: {
m: function(x) {
var that = this;
setTimeout(function() {
that.inherited();
}, 2000);
},
bla: function() {
// do stuff
}
}
});
var df = new DoubleFoo();
df.m(1);
df.bla();
But with the approach from Cls (specifying inherited with name of super
function and arguments) this does work properly (although more verbose).
On Wednesday, May 23, 2012 2:09:49 PM UTC+3, Nodir Turakulov wrote:
>
> On Wed, May 23, 2012 at 4:00 PM, Nodir Turakulov <[email protected]>
> wrote:
> > On Wed, May 23, 2012 at 2:17 PM, alessioalex <[email protected]>
> wrote:
> >> I've made a OOP module myself a couple of days ago:
> >> https://github.com/alessioalex/Cls
> >>
> >> It uses an extends function and a mixin function under the hood, very
> basic
> >> stuff.
> >
> > As far as I understand after a quick look at the readme, your mixins
> > only overwrites properties without inheriting methods
>
> Sorry, the word "inheriting" is wrong here. I meant that a mixin
> method cannot call a base method.
>
> -Nodir
>
> > Can I call a base/super method in a mixin method?
> >
> > var foo = Cls({
> > methods: {
> > m: function (x) {
> > console.log(x);
> > }
> > }
> > });
> >
> > var mixin = {
> > m: function (x) {
> > this.inherited(x * 1);
> > }
> > };
> >
> > var doubleFoo = Cls.mixin(foo, mixin);
> > doubleFoo.m(1); // will it output 1 or 2?
> >
> > -Nodir
> >
> >> --
> >> Job Board: http://jobs.nodejs.org/
> >> Posting guidelines:
> >> https://github.com/joyent/node/wiki/Mailing-List-Posting-Guidelines
> >> You received this message because you are subscribed to the Google
> >> Groups "nodejs" group.
> >> To post to this group, send email to [email protected]
> >> To unsubscribe from this group, send email to
> >> [email protected]
> >> For more options, visit this group at
> >> http://groups.google.com/group/nodejs?hl=en?hl=en
>
--
Job Board: http://jobs.nodejs.org/
Posting guidelines:
https://github.com/joyent/node/wiki/Mailing-List-Posting-Guidelines
You received this message because you are subscribed to the Google
Groups "nodejs" group.
To post to this group, send email to [email protected]
To unsubscribe from this group, send email to
[email protected]
For more options, visit this group at
http://groups.google.com/group/nodejs?hl=en?hl=en
