this is crazy
i think that what Anand is might want to do is this:
function addAsync(no1, no2, cb)
{
process.nextTick(function() {
res = no1 + no2;
cb(null, res);
});
};
addAsync(1, 2, function(err, res) {
console.log(res);
});
in order to queue the *intensive CPU operation of adding two numbers* for
the next tick in the event loop..
2012/6/6 Oliver Leics <[email protected]>
> On Wed, Jun 6, 2012 at 3:31 PM, Anand George <[email protected]>
> wrote:
> > When I run this code I get the following output.
> >
> > 3
> > 6
> > 3.
> >
> > Any ideas why this could be happening.
>
> This happens because the code does what it has to do.
>
> > It's forcing the calling function to run again.
>
> I don't understand that. What did you expect? Maybe only one line with
> 3? But the code calls the callback two times.
>
> ???
>
> :-)
>
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