pardon me for the (cur % 2) == 0 part, completely unnecessary to your case

On Tue, Oct 30, 2012 at 8:36 PM, Felipe Mobus <[email protected]> wrote:
> You could use ES5's array.reduce() method, but it's gonna be a bit ugly
>
> [1,2,3,4,5,6,7,8].reduce(function(prev, cur) {
>   prev[cur] = (cur % 2) == 0;
>   return prev;
> }, {})
>
> On Tue, Oct 30, 2012 at 8:25 PM, mscdex <[email protected]> wrote:
>> On Oct 30, 5:50 pm, Felipe Gasper <[email protected]> wrote:
>>> Anything of the sort coming in JS, does anyone know? Maybe in some of
>>> the newer ES5 goodies?
>>
>> Does this help?: 
>> https://github.com/joyent/node/wiki/ECMA-5-Mozilla-Features-Implemented-in-V8
>>
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>
>
>
> --
> Felipe Mobus
> http://fmobus.wait4.org



-- 
Felipe Mobus
http://fmobus.wait4.org

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