> The 'readable' event fires as soon as *any* data is added to the
> internal buffer, but only if a previous read() call returned null. If
> you never got a null read, then you haven't exhausted the buffer, so
> there's no need to emit 'readable', since presumably you already know
> it's readable.
Is needReadable set to true when you create the socket or do I have to call
read() right after making the socket?
I looked through the ReadableStream code and couldn't find a path that sets
it to true. I'm using new fs.ReadStream(null, {fd: 4}).
On Monday, May 6, 2013 4:59:39 PM UTC-4, Isaac Schlueter wrote:
>
> > Basically the loop is because the "readable" event doesn't fire until
> the buffer is filled up and if you want to get data immediately, then you
> can't rely on "readable"?
>
> The 'readable' event fires as soon as *any* data is added to the
> internal buffer, but only if a previous read() call returned null. If
> you never got a null read, then you haven't exhausted the buffer, so
> there's no need to emit 'readable', since presumably you already know
> it's readable.
>
> > It would seem (from the docs) that read() without any limit returns the
> whole buffer, so how would there be more data the next time you call it?
>
> The length of the returned data from read() is implementation-defined.
> In objectMode streams, it'll always be one "thing", but in
> binary/string streams it can be any amount of data.
>
> If you're using the stream.Readable base class, then yes, read() will
> always return the full buffer, *unless* you're piping, in which case,
> it returns the top chunk in the list, so as to avoid an unnecessary
> copy in the case where there's more than one chunk ready.
>
>
> On Mon, May 6, 2013 at 11:10 AM, James Hartig
> <[email protected]<javascript:>>
> wrote:
> > Sorry to be late to the party...
> >
> > Basically the loop is because the "readable" event doesn't fire until
> the
> > buffer is filled up and if you want to get data immediately, then you
> can't
> > rely on "readable"?
> >
> > It would seem (from the docs) that read() without any limit returns the
> > whole buffer, so how would there be more data the next time you call it?
> >
> >
> > On Sunday, April 14, 2013 4:57:49 PM UTC-4, Jorge wrote:
> >>
> >> On 30/03/2013, at 00:56, Isaac Schlueter wrote:
> >>
> >> > ```javascript
> >> > var chunk;
> >> > while (null !== (chunk = rs.read())) {
> >> > doSomething(chunk);
> >> > }
> >> > ```
> >>
> >> I use to write code like that too but it might break it seems, look:
> >>
> >> <https://bugs.webkit.org/show_bug.cgi?id=114594>
> >>
> >> this works:
> >>
> >> function works (s) {
> >> var pos;
> >> var n= 0;
> >> var t;
> >> var r= "";
> >> var o=
> "0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ";
> >> var p=
> "5678901234nopqrstuvwxyzabcdefghijklmNOPQRSTUVWXYZABCDEFGHIJKLM";
> >> while (n < s.length) {
> >> t= s[n];
> >> pos= o.indexOf(t);
> >> r+= (pos >= 0) ? p[pos] : t;
> >> n++;
> >> }
> >> return r;
> >> }
> >>
> >> this doesn't:
> >>
> >> function fails (s) {
> >> var pos, n = 0,
> >> t, r = "",
> >> o =
> "0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ",
> >> p =
> "5678901234nopqrstuvwxyzabcdefghijklmNOPQRSTUVWXYZABCDEFGHIJKLM";
> >> while (n < s.length) {
> >> r += ((pos = o.indexOf(t = s[n++])) >= 0) ? p[pos] : t;
> >> }
> >> return r;
> >> }
> >>
> >> --
> >> ( Jorge )();
> >
> > --
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