On Monday, November 4, 2013 6:39:27 AM UTC-5, David Clements wrote: > > Hey thanks mscdex, yeah I see that, so I must be misunderstanding how it > works, I would have though that the number passed to read would > carry through to _read, but instead the read method uses it's n parameter > independently and always passes in the high water mark? > > My guess is efficiency/performance (reading one large Buffer vs reading x individual smaller Buffers possibly needing concatenation to reach n). Another thing to remember is that `read(n)` will return *at least* n bytes.
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