Hello!

I think you are a bit confused about endians and buffer representation
in console. When you type `myBuff` it prints bytes in the same order
as they'll be sent on network or written to file.

i.e. `<Buffer 36 02 00 00>` means that `buf[0] === 0x36` and `buf[1]
=== 0x02`, which is exactly how Little Endian should be represented.
The big endian representation of your number will be 00000236 which
means that  `buf[2] === 0x02` and `buf[3] === 0x36`.

Cheers,
Fedor.

On Thu, Feb 27, 2014 at 12:30 PM, jduncanator <[email protected]> wrote:
> Correct me if I'm wrong but I think there is an issue with the way Buffer's
> endianness works (or at least the "description" the methods have).
>
> Lets say I create a new buffer:
>
> var myBuff = new Buffer(4);
>
> And now I wish to write an integer to my buffer in little-endian which has
> the least significant byte first:
>
> myBuff.writeUInt32LE(566, 0);
>
> Now then, one would expect that this method just wrote the integer '566' to
> my buffer in little-endian, but something odd goes on:
>
>> myBuff
> <Buffer 36 02 00 00>
>
> Hang on, thats not little-endian, thats big-endian. If I were to send this
> over the network now, and the other end expects the buffer to contain a
> integer in little-endian, they would be rudely interrupted with a big-endian
> integer. You can even demonstrate this by entering that hex into the
> interpreter:
>
>> 0x36020000
> 906100736
>
> Am I confusing what the BE and LE mean in the `write` functions or is
> something weird going on?
>
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