Returning works in mysterious ways :P
Okay, maybe this can help you get a grasp of what you are doing..
Fire up your node REPL.
By executing node without any arguments from the command-line you will be
> dropped into the REPL.
And try this:
function test (a, cb) {
console.log("inside test function.. test parameter value is: ", a);
console.log("Back to test again, the value is returned from the callback:
", cb(a+1));
}
test(0, function (b) {
console.log("inside the anonymous function provided as callback to test");
console.log("the value of anonymous parameter is: ", b);
return b+1;
});
The anonymous function returned value only has meaning because the function
that called it is expecting a value.
The function that accepts a callback is the one that receives the return
value from the callback.
This example was only to clarify who gets your returned value.
Another point: observe that the return statement of the function you pass
as a callback to connection.query
is *not* the return of your main function -code that follows the callback
in the outermost braces also gets executed.
Oh, and it doesn't matter (at least regarding the return statement) whether
you provide a named or an anonymous function
as a callback. Try this:
copy paste:
function test (a, cb) {
console.log("inside test function.. test parameter value is: ", a);
console.log("Back to test again, the value is returned from the callback:
", cb(a+1));
}
and then:
function namedFunction (b) {
console.log("inside \'namedFunction\' provided as callback to test
function..");
console.log("namedFunction parameter has the value: ", b);
return b+1;
}
and run:
test(0, namedFunction);
On Wednesday, May 21, 2014 4:22:55 PM UTC+3, Janos wrote:
>
> Hi there,
>
>
> [..]
>
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