> I want to sep through my child_process code like a debugger.
>
I read this as "I want to have link between child and parent and control
logic of the child".
With child_process.fork() you already have this link, exposed as
on('message')
<http://nodejs.org/api/child_process.html#child_process_event_message> and
send(message
<http://nodejs.org/api/child_process.html#child_process_child_send_message_sendhandle>
)
I habve try it with the bild in debugger but how can i concrol the debugger
> from the parent process ?
>
Yes, you can (though I doubt it's a good solution for your problem)
1) spawn your child with debugger enabled
var child = spawn('node', ['--debug-brk', 'script.js', 'some', 'params'
]);
2) connect debugger client from parent:
var DebuggerClient = require('_debugger').Client;
var dc = new DebuggerClient();
dc.connect(5858);
3) add some breakpoints to your script with "debugger" keyword or
programmitically with dc.setBreakpoint()
<https://github.com/joyent/node/blob/master/lib/_debugger.js#L466>
4) drive your it with calls to dc.step()
<https://github.com/joyent/node/blob/master/lib/_debugger.js#L496>,
dc.recContinue()
<https://github.com/joyent/node/blob/master/lib/_debugger.js#L457> and by
reacting on break events:
dc.on('break', function(resp) { /* your child stopped */ });
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