On Wednesday, October 25, 2017 at 7:38:37 AM UTC+2, [email protected]
wrote:
>
> Here is my code. Its a simple one
> for(var a=0; a<dResponse.length;a++ ){
> var dId = dResponse[a].dId;
> console.log('dId-->' +dResponse);
> var dUrl = url?id=' + dId;
> console.log('Url:'+dUrl);
> }
> Every time it returns the same url.
>
>>
>>
You didn't show the whole code - what's in dResponse array? But, your title
says "Synchronous for loop", depending on your node version, here's a
simple example:
const request = require('request');
function callRemoteApi(url) {
return new Promise((resolve, reject) => {
console.log('Fetching', url);
request(url, (err, res) => {
if (err) {
return reject(err);
}
console.log('Got', url);
const result = JSON.parse(res.body).url;
resolve(result);
});
});
}
async function runTest() {
const urls = [
'https://httpbin.org/delay/5',
'https://httpbin.org/delay/1',
'https://httpbin.org/delay/3',
];
console.log('Urls ready.');
let promises = [];
for (let url of urls) {
promises.push(callRemoteApi(url));
};
console.log('Promises ready.');
await Promise.all(promises.map(async promise => console.log('Result of
promise:' + await promise)))
.then(() => console.log('All done.'));
}
runTest();
Now, if you run this code, it'll show you how things are working.
So the for loop example is indicative of potential issues with sync for
loops. It takes an url, *waits* for it to return, and then goes on to the
next.
Now, the other example works much better: we execute all promises
immediately, in parallel. And as they come back, we get the results logged
immediately.
Not sure how applicable this is to your situation, but if you post more
code, we might help out.
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