We're children and it's sums today
it is very easy to remember/make sums of paired numbers 2+2=4 5+5=10 8+8 is harder that's a three stepper that goes like 10-8=2; 8-2=6 ; 10+6=16 The movements how do they feel like? We don't remember, they have been erased almost entirely by other movements in the same space tey are absences within absences within carvings out of the possible into the actual bam bam + fall forward twice as high as bam goes down? Tjak tjak & float till you can grab the chopped off/ carved out piece? Three steps: a-b=c b-c= d a+d= where we want to be we learn to keep on thinking a while we work out the differences? The cycle goes up to ten so we have 10 cycles going up to ten in a cycle of ten Do we use two cycles of ten for the pairs of 2, of all below 6 How many for the other Ha: the a is not on the same level as the b and c and d It's a complete cycle A whole new universe (dump the old one) So in fact it may be more like here's the sum (8+8) start a cycle (this is the 10) Darn the pairs don't fit in the cycle (it takes longer mama) Start a new cycle to see how long it doesn't fit Drag the cycle to a third one stopping at 8 Rerun it inverse on the second 8 Catch the difference in a fourth Fold that back on the 10 Unfold the total. Voila. Mums I did it (16) Why [cause] : (it is not static variables it's running cycles) Why [purpose]: (please mama)
