rohitkrishna-marneni opened a new issue, #12023:
URL: https://github.com/apache/apisix/issues/12023
### Description
I want to create a plugin where if upstream status is 404, I will be able to
specify a custom 404 page and it should go there.
So this is what I have so far.
My apisix configuration for route
```yml
services:
- name: my-service
upstream:
pass_host: pass
nodes:
- host: my-api.com
port: 80
weight: 1
priority: 0
type: roundrobin
scheme: http
name: my-api
hash_on: vars
timeout:
send: 10
read: 60
connect: 2
routes:
- name: my product page route
hosts:
- "mysite.com"
uris:
- /shop/products/*
priority: 0
plugins:
custom-404-redirect:
redirect_url: /us/en/footer/terms-conditions.html
```
And my plugin code is as shown below
```lua
local core = require("apisix.core")
local ngx = ngx
local plugin_name = "custom-404-redirect"
local schema = {
type = "object",
properties = {
redirect_url = {type = "string", minLength = 1}
},
required = {"redirect_url"}
}
local _M = {
version = 0.1,
priority = 1010, -- set the plugin priority, higher means earlier
execution
name = plugin_name,
schema = schema
}
function _M.check_schema(conf)
return core.schema.check(schema, conf)
end
function _M.header_filter(conf, ctx)
if ngx.status == 404 then
ngx.status = 302
ngx.header["Location"] = conf.redirect_url
ngx.log(ngx.ERR, "Redirecting to custom 404 page: ",
conf.redirect_url)
ngx.exit(ngx.HTTP_MOVED_TEMPORARILY)
end
end
return _M
```
But this is not working and simply throwing a 500 status code instead of
going to a 404 as expected. Is it not possible to do it via plugin?
### Environment
- APISIX version (run `apisix version`):
- Operating system (run `uname -a`): Ubuntu
- OpenResty / Nginx version (run `openresty -V` or `nginx -V`):
- etcd version, if relevant (run `curl
http://127.0.0.1:9090/v1/server_info`):
- APISIX Dashboard version, if relevant:
- Plugin runner version, for issues related to plugin runners:
- LuaRocks version, for installation issues (run `luarocks --version`):
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