qianjunakasumi commented on issue #4255: URL: https://github.com/apache/apisix/issues/4255#issuecomment-841632289
@tokers Thank you for your reply :), but it's not the expected... When I request an undefined route, APISIX usually returns a 404 status code BUT I want to directly **DENY**( 444 code ? ) rather than return status code when requesting IP by this way could protects my application, which must be protected by CDN to reach the original server. Thank you again for your reply. --- @tokers 谢谢你的回复:)，但它不是预期的... 当我请求未定义的路由时，APISIX 通常会返回 404 状态码 但我希望请求 IP 时，直接阻断而不是返回状态码 这样可以保护我的应用程序必须经过CDN的保护才能到达源服务器 再次感谢你的回复 -- This is an automated message from the Apache Git Service. To respond to the message, please log on to GitHub and use the URL above to go to the specific comment. For queries about this service, please contact Infrastructure at: [email protected]
