chickenlj commented on issue #10165:
URL: https://github.com/apache/dubbo/issues/10165#issuecomment-1235032187
因为你传的参数值是 Json 格式的
> Map<String, Object> result = (Map<String, Object>)
genericService.$invoke(method, new String[]{param.getClass().getName()}, new
Object[]{JSONObject.toJSONString(param)});
这个方法也尝试下 reference.setGeneric("gson"); 或者 reference.setGeneric("json");
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