worker24h opened a new issue, #11599: URL: https://github.com/apache/dubbo/issues/11599
我需要实现广播方式,例如 interface A { void notifySyncRoute(); bool notifyRoute(Meta route); } @DubboService class AA implements A { public notifySyncRoute() { ... notifyRoute(route); //广播, 复用dubbo的另外一个接口,实现广播方式 ... } public notifyRoute(Meta route) { ... // doing ... } } 不知道能否实现? 如何实现?感谢 -- This is an automated message from the Apache Git Service. To respond to the message, please log on to GitHub and use the URL above to go to the specific comment. To unsubscribe, e-mail: notifications-unsubscr...@dubbo.apache.org.apache.org For queries about this service, please contact Infrastructure at: us...@infra.apache.org --------------------------------------------------------------------- To unsubscribe, e-mail: notifications-unsubscr...@dubbo.apache.org For additional commands, e-mail: notifications-h...@dubbo.apache.org