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https://issues.apache.org/jira/browse/GROOVY-9909?page=com.atlassian.jira.plugin.system.issuetabpanels:all-tabpanel
]
Paul King closed GROOVY-9909.
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> Cannot call super when overriding an interface default method
> -------------------------------------------------------------
>
> Key: GROOVY-9909
> URL: https://issues.apache.org/jira/browse/GROOVY-9909
> Project: Groovy
> Issue Type: Bug
> Components: Static compilation, Static Type Checker
> Affects Versions: 2.5.14
> Reporter: Mauro Molinari
> Assignee: Eric Milles
> Priority: Major
> Labels: default-methods
> Fix For: 4.0.0-rc-2
>
>
> Suppose you have:
> {code:java}
> public interface MyInterface {
> default String getFoo() { return "foo"; }
> }
> {code}
> and a Groovy class implementing it:
> {code:groovy}
> @CompileStatic
> class MyClass implements MyInterface {
> @Overridde
> String getFoo() {
> return MyInterface.super.getFoo();
> }
> }
> {code}
> This produces multiple compiler errors, like:
> {noformat}
> - Groovy:[Static type checking] - No such property: super for class:
> java.lang.Class <MyInterface>
> - Groovy:The usage of 'Class.this' and 'Class.super' is only allowed in
> nested/inner classes
> {noformat}
> If I replace it with:
> {code:groovy}
> @CompileStatic
> class MyClass implements MyInterface {
> @Overridde
> String getFoo() {
> return super.getFoo();
> }
> }
> {code}
> I get:
> {noformat}
> Groovy:[Static type checking] - Cannot find matching method
> java.lang.Object#getFoo(). Please check if the declared type is correct and
> if the method exists
> {noformat}
> I find no way to properly override a default method while calling the super
> implementation.
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