[shardingsphere] branch master updated: Update rewrite.cn.md (#9097)

[panjuan]

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The following commit(s) were added to refs/heads/master by this push:
     new 958cbcc  Update rewrite.cn.md (#9097)
958cbcc is described below

commit 958cbcca8a09bed1ef21b3db3457315bd3fc4622
Author: MingHao Li <lmhlmh...@163.com>
AuthorDate: Wed Jan 20 12:08:46 2021 +0800

    Update rewrite.cn.md (#9097)
---
 docs/document/content/features/sharding/principle/rewrite.cn.md | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)

diff --git a/docs/document/content/features/sharding/principle/rewrite.cn.md 
b/docs/document/content/features/sharding/principle/rewrite.cn.md
index 9554a66..1e98e52 100644
--- a/docs/document/content/features/sharding/principle/rewrite.cn.md
+++ b/docs/document/content/features/sharding/principle/rewrite.cn.md
@@ -187,7 +187,7 @@ SELECT score FROM t_score ORDER BY score DESC LIMIT 1, 2;
 
![不改写SQL的分页执行结果](https://shardingsphere.apache.org/document/current/img/sharding/pagination_without_rewrite.png)
 
 通过图中所示，想要取得两个表中共同的按照分数排序的第 2 条和第 3 条数据，应该是 `95` 和 `90`。
-由于执行的 SQL 只能从每个表中获取第 2 条和第 3 条数据，即从 t_score_0 表中获取的是 `90` 和 `80`；从 t_score_0 
表中获取的是 `85` 和 `75`。
+由于执行的 SQL 只能从每个表中获取第 2 条和第 3 条数据，即从 t_score_0 表中获取的是 `90` 和 `80`；从 t_score_1 
表中获取的是 `85` 和 `75`。
 因此进行结果归并时，只能从获取的 `90`，`80`，`85` 和 `75` 之中进行归并，那么结果归并无论怎么实现，都不可能获得正确的结果。
 
 正确的做法是将分页条件改写为 `LIMIT 0, 3`，取出所有前两页数据，再结合排序条件计算出正确的数据。