bito-code-review[bot] commented on code in PR #40670: URL: https://github.com/apache/superset/pull/40670#discussion_r3393780219
########## superset/security/password_complexity.py: ########## @@ -0,0 +1,121 @@ +# Licensed to the Apache Software Foundation (ASF) under one +# or more contributor license agreements. See the NOTICE file +# distributed with this work for additional information +# regarding copyright ownership. The ASF licenses this file +# to you under the Apache License, Version 2.0 (the +# "License"); you may not use this file except in compliance +# with the License. You may obtain a copy of the License at +# +# http://www.apache.org/licenses/LICENSE-2.0 +# +# Unless required by applicable law or agreed to in writing, +# software distributed under the License is distributed on an +# "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY +# KIND, either express or implied. See the License for the +# specific language governing permissions and limitations +# under the License. +"""Superset password-complexity validator. + +Wired in via ``FAB_PASSWORD_COMPLEXITY_VALIDATOR`` (with +``FAB_PASSWORD_COMPLEXITY_ENABLED``). Flask-AppBuilder runs this callable from +both the WTForms password fields (self-registration, user edit, reset password) +and the User REST API, so a single function enforces the policy across all +password-setting flows. + +The default policy is a minimum length plus a common-password blocklist — +intentionally less draconian than FAB's built-in ``default_password_complexity`` +(which requires 2 uppercase, 1 special, 2 digits, 3 lowercase and length 10). +""" + +from __future__ import annotations + +from flask import current_app +from flask_appbuilder.exceptions import PasswordComplexityValidationError +from flask_babel import gettext as __ + +# A small built-in blocklist of the most common/guessable passwords. Operators +# can extend it with AUTH_PASSWORD_COMMON_BLOCKLIST. (A fuller list or a +# Have-I-Been-Pwned k-anonymity check is a possible follow-up.) +COMMON_PASSWORDS: frozenset[str] = frozenset( + { + "123456", + "123456789", + "12345678", + "1234567890", + "12345", + "111111", + "123123", + "000000", + "password", + "password1", + "password123", + "passw0rd", + "qwerty", + "qwerty123", + "qwertyuiop", + "abc123", + "letmein", + "welcome", + "welcome1", + "admin", + "admin123", + "administrator", + "root", + "superset", + "changeme", + "iloveyou", + "monkey", + "dragon", + "sunshine", + "princess", + "football", + "baseball", + "trustno1", + "login", + "master", + "hello123", + "secret", + "default", + } +) + +DEFAULT_MIN_LENGTH = 8 + + +def validate_password_complexity(password: str) -> None: + """Validate a plaintext password against the configured policy. + + :raises PasswordComplexityValidationError: if the password is too short or + appears in the common-password blocklist. + """ + raw_min_length = current_app.config.get( + "AUTH_PASSWORD_MIN_LENGTH", DEFAULT_MIN_LENGTH + ) + # Operators commonly wire config via env vars, so AUTH_PASSWORD_MIN_LENGTH can + # arrive as a string (or be left unset/None). Coerce defensively and fall back + # to the default rather than blowing up every password-setting flow with a + # TypeError on the length comparison. + try: + min_length = int(raw_min_length) + except (TypeError, ValueError): + min_length = DEFAULT_MIN_LENGTH + + if len(password) < min_length: + raise PasswordComplexityValidationError( + __( + "Password must be at least %(min_length)s characters long.", + min_length=min_length, + ) + ) + + extra = current_app.config.get("AUTH_PASSWORD_COMMON_BLOCKLIST") or [] + # A bare string is iterable but would be split into characters, so treat a + # misconfigured string as a single entry. casefold() gives correct + # case-insensitive matching for non-ASCII passwords too. + if isinstance(extra, str): + extra = [extra] + blocklist = COMMON_PASSWORDS | {str(item).casefold() for item in extra} + if password.casefold() in blocklist: Review Comment: <!-- Bito Reply --> The concern regarding literal comparison is noted. If the intention is to block only exact matches of common passwords and avoid rejecting valid passwords that happen to contain common substrings, maintaining the current literal comparison is appropriate. The proposed change would indeed normalize input, which could lead to rejecting passwords that are not in the blocklist but contain common patterns as substrings. **superset/security/password_complexity.py** ``` blocklist = COMMON_PASSWORDS | {str(item).casefold() for item in extra} - if password.casefold() in blocklist: + # Strip whitespace before blocklist check to prevent bypassing with padded + # common passwords (e.g., " password123 " should be rejected like "password123"). + if password.strip().casefold() in blocklist: ``` -- This is an automated message from the Apache Git Service. To respond to the message, please log on to GitHub and use the URL above to go to the specific comment. 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