If you plug the values in the formula PER=1-(1-0.001)^8000 = 0.9996658
The above result implies that 99.96% of you packets will have errors and if there are no additional error correction mechanisms, they will be dropped/lost. A BER of 10^-3 is too high and is not practical. For example, in most wireless scenarios, the BER is assumed to be 10^-6. By the way, why are you posting this in ns-users list? Abdul. 林泰邑 wrote: > for example : > when I give ber=10^-3, packet size=1000bytes, what is PER? > > -----Original Message----- > From: Abdul Jabbar [mailto:[EMAIL PROTECTED] > Sent: Monday, October 02, 2006 6:24 PM > To: 林泰邑 > Cc: ns-users@isi.edu > Subject: Re: [ns] how do i transfrom "Bit Error Rate" to "Packet Error > Rate"? > > As far as I know, the relationship between BER and PER , assuming that > bit errors are independent and uniformly distributed is, > > PER=1-(1-BER)^N where N is the number of bits. > > However, the above formula is only approximate because in real life > scenarios, the bit errors are not completely independent but may occur > in bursts. Further, the error distribution is also not exactly uniform. > > Hope it helps.... > > Cheers, > Abdul. > > 林泰邑 wrote: > >> ------------------------------------------------------------------------ >> >> Hi all, how can I transform “Bit error Rate” to “packet error rate”? >> >> >> >> Is there any formulas for this ? >> >> >> >> Can any body help me? >> >> >> >> >> > > > > >
