Dear Vishal,
It won't. The reason is because you attach two TCP agents to two nodes. Each node attach to different link. But the packets generated by both TCP agents will go to the same place. When the packets reach the destination, it would simply be destroy. Of course, the contention would be at the link connecting "into" the sink node. But that is the nature of packets sharing the node. For more information about Links, Nodes, Agents and Applications, see the following book from Springer: T. Issaraiyakul and E. Hossain, "Introduction to Network Simulator NS2", Springer 2008. http://www.springer.com/engineering/signals/book/978-0-387-71759-3 You may also find the following website useful: http://www.ece.ubc.ca/~teerawat/NS2.htm On 5/27/2009, "Vishal Agarwal" <[email protected]> wrote: >But would both the agents will fight for channel contention or packets from >both the sources will go regardless of transmission from other end..?? > >On Wed, May 27, 2009 at 9:56 PM, Teerawat Issariyakul ><[email protected]>wrote: > >> >> Dear Vishal, >> >> Only one sink is necessary. But you do need to connect both tcp agent to >> the same sink by using "$ns connect $tcp1 $sink" and "$ns connect >> $tcp2 $sink". The result would be the same as when you have two sinks. >> >> Best, >> Teerawat >> >> On 5/27/2009, "Vishal Agarwal" <[email protected]> wrote: >> >> > >> >Hello users, >> > >> >I am attaching 2 tcp agents at one source so do i need to attach 2 sinks >> at >> >destination also or only 1 is sufficient. And when the agent tries to >> access >> >the channel will there be any difference if there are two sinks rather >> than >> >one? >> > >> >Thanks, >> > >> >-- >> >Vishal Agarwal >> > >> > > > >-- >Vishal Agarwal
