So if I want to find the throughput of all the network vs time how would I go about it using the trace file, or the queue size vs time?
I would like for an explanation with the reasoning behind it. I know that to get the throughput for a connection in a link you just add up the received packets every interval and divide (for instance the interval can be a second, you add 10 packets of 1500bytes so at that second you have throughput of 15000Bps or 120000bps) but what do you do for a whole network? Do you add up all the received packets in all the links and all connections and divide and the optimum or maximum throughput is the addition of the bandwidths of all the links to the servers? I am simulating a fat-tree datacenter so I am not sure if I should just process the links to the hosts and not all the in between nodes. I have the same questions about queue sizes though in that case I think I have to average the queue length of EVERY link there is in the network, not only the links to the hosts. Any hints, corrections, advise appreciated. On 11/04/2014 18:42, Miguel RodrÃguez wrote: > Of course, you just can use the trace file. It is the most important. > The nam file, I have used just for see what happen graphically. > > So, analyzing ".tr" file you can accomplish you want to do. > > Regards. > > > 2014-04-11 11:47 GMT-05:00 Andreas Andreou <[email protected] > <mailto:[email protected]>>: > > > I am running simulations for my project and I have both nam files > (/namtrace-all/) and trace files (/trace-all/) recording. The namfile > ends up in the order of ~15GB for 5 sec of simulation and the trace > files in the order of ~5GB. My question is do I need both or can I > just > choose one. I know that the nam is bigger because it must record > for the > nam animator as well so can I assume that the tracefile is a subset of > the namfile. Can I do the processing I want (throughput, > queuesize, flow > completion time, latency, etc) using just one of those files? > > > --- > This email is free from viruses and malware because avast! > Antivirus protection is active. > http://www.avast.com > > --- This email is free from viruses and malware because avast! Antivirus protection is active. http://www.avast.com
