At 12:31 AM 7/7/2005, Frank Grieshaber wrote:
Hello all (esp. the ConTeXt-Developers),
some time ago I sent the following email to this list and got no reply so
I'm resending it.
Dear all,
I have a manuscript with long nested numbered enumerations and I want the
numbers of all levels to be printed automatically like:
1. one
1.1 one-one
1.2 one-two
2. two
2.1 two-one
2.2.1 two-two-one
...
Using the following prints only the current level's number, not all levels:
\startitemize[n,packed]
\item
\item
\startitemize[m,packed]
\item
\item
\stopitemize
\item
\item
\stopitemize
For Latex there is the package paralist.sty for doing the desired
numbering, how can this be done with ConTeXt?
(I wrote this before I noticed that Hans had already replied, but I'm
sending this anyway in case someone finds it useful.)
I just accidentally solved this problem, in some of the LaTeX-compatibility
stuff that I've been working on. Have a look at t-ltenum.tex for the
kernel code that does it, and latextest.tex for an example of how to use it
for something akin to that effect. It's fairly self-contained; you should
be able to use t-ltenum.tex, t-ltcnts (which does counters) and
t-ltbase.tex to get the "LaTeX-style enumerations" working, without needing
any of the other bits. All my current files are in this repository:
http://dpdx.net/context/latex-compat/
That's sort of the long way around to doing what you're looking for,
though, and you can get the same effect without the LaTeX-compatibility
overhead. Here's the trick....
First, you create a set of "conversions" for each level of the list -- see
the Wiki page linked off "Enumerations" for how to do that. The conversion
for level one will look something like this:
\def\listconversioni{%
\edef\listheadi{\numbers{#1}.}%
\numbers{#1}}
\defineconversion[listconvi][\listconversioni]
That returns the list-counter in number form, but it also stores it (with a
"." after it) in a "header". (I don't know whether that should be \edef or
just \def, but I _think_ \edef is right.)
Then, the conversion for level two looks something like this:
\def\listconversionii{%
\edef\listheadii{\listheadi\numbers{#1}.}%
\listheadi\numbers{#1}}
\defineconversion[listconvii][\listconversionii]
That does the same thing, but now it's prefixing it with \listheadi. This
then continues down the list as deep as you want to go. You then do a
\defineitemgroup and some \setupitemgroup commands (again, see the Wiki's
"Enumerations" page) to set it so that each one of those is associated with
the appropriate level, and off you go; it's all automatic from there.
Depending on whether \startitemize / \stopitemize includes grouping or not
(and on exactly where that grouping is placed), it may be possible to do
this in a more general form -- have \startitemize execute some code to set
\parentlisthead to the current \listhead (which comes from the next level
up), and then have one conversion for all levels which uses \parentlisthead
and defines a new \listhead to be used on any child itemizations. The
trick here is that \stopitemize will (hopefully) contain a \endgroup or
\egroup, so that after it the \listhead value will revert to what it was
before the corresponding \startitemize. This has the advantage of being
able to go arbitrarily deep, but you can't do things like "1.a" where the
levels are enumerated differently.
There are, of course, variations on all of these, but that general idea
should be enough to get you going.
And I'll second the recommendation that something like this ought go in the
kernel; I'm actually rather surprised that it's not already in there!
Actually, what I would specifically suggest is that the \item code should
place the converted item counter -- the result of calling \doconversion --
into something like \currentitemlabel, and then \startitemize should move
that to \parentitemlabel, all automatically, so one can simply define
conversions with \parentitemlabel in them without having to implement the
machinery oneself.
Or ... ah, wait; I see that Hans already replied to this shortly after you
posted, and I missed it. Oh, well; I'll send this anyway. :)
- Brooks
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