Here in Terminal on my Mac:
21 ~: lua
Lua 5.4.6 Copyright (C) 1994-2023 Lua.org, PUC-Rio
> string.gsub('a%20b', '%%20', ' ')
a b 1
> (string.gsub('a%20b', '%%20', ' '))
a b
> ^D
21 ~:
The first call returns the 1 giving the match, the extra ()'s get rid of that
second return value.
yours sincerely
dr. Hans van der Meer
> On 21 Jul 2023, at 12:37, [email protected] wrote:
>
> Hi,
>
> I’m typesetting an XML document where the links to the images contain spaces
> which are encoded as %20
> <graphic xlink:href="a%20filename%20with%20spaces.jpg"/>
>
> Using this works in cases without spaces:
>
> \startxmlsetups xml:fig:graphic
> \externalfigure[\xmlatt{#1}{xlink:href}]
> \stopxmlsetups
>
> This also works for normal spaces, but is there a way to decode/expand the
> %20s to regular spaces?
>
> I’ve tried with some Lua, but I don’t really know how to pass data around.
>
> %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
> \startluacode
> function replaceSpaces(s)
> result = string.gsub(s, "%%20", " ")
> context(result)
> end
> \stopluacode
>
> \define[1]\replaceSpaces{\ctxlua{replaceSpaces("#1")}}
>
> \startxmlsetups xml:fig:graphic
> \externalfigure[\replaceSpaces{\xmlatt{#1}{xlink:href}}]
> \stopxmlsetups
> %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
>
> Any hints, why this does not work?`
>
> Also, maybe there’s a simpler way for this kind of scenario?
>
> Best,
> Denis
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