On Sun, 31 Oct 2010, Wolfgang Schuster wrote:
Am 31.10.2010 um 01:27 schrieb Aditya Mahajan:
Hi,
I want to write a macro that checks for some settings and if the settings are
wrong stop the current compilation and terminate with an error message. Right
now I have
\def\ERROR
{\writeline
\showmessage\??externalfilter??{forbidden}\getexternalfilterdirectory
\batchmode
\normalend}
This prints the error message on the terminal and exits. However the exit
status (the value of $?) is 0, if the tui file has changed the document is
compiled a second time anyways.
How can I force context (the macro package) to exit with a status of 1 so that
context (the program) does not attempt a second compilation?
\starttext
one
\scrollmode\undefined\forcequitjob{bye}
two
\stoptext
\forcequitjob is defined in the same manner as my definition
\def\forcequitjob#1%
{\writestatus\m!systems{forcing quit: #1}%
\batchmode
\dorecurse\textlevel{\stoptext}
\normalend}
and suffers from the same problem. It does not send the program's error
code to 1. After compiling
\starttext
\forcequitjob{bye}
\stoptext
the output of `echo $?` is 0, so context thinks that the program compiled
sucessfully.
Now add
\section{one}
on the first line and compile again. Context does two runs of the program
(because no error signal is generated at the end of the first run). I want
to avoid this second run.
Aditya
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