This works fine:
\starttext Here a type macro <\type{\abc}> \stoptext
This also:
\starttext \placetable{table \type{abc} title}{abc} \stoptext
This too:
\starttext \placetable{table \type{\blank} title}{abc} \stoptext
But this gives an error (mind the \ before abc).
\starttext \placetable{table \type{\abc} title}{abc} \stoptext
Do I misinterprete something here?
I just wanted to typeset "\abc" in the type-font.
Why is the very first \abc treated as text to typeset but requires the
placetable argument that it is an existing macro?
Or isn't this the intended behaviour?
Hans van der Meer
Error log:
system > tex > error on line 3 in file test.tex: Undefined control
sequence ...
1 \starttext
2 %Here a type macro <\type{\abc}>
3 >> \placetable{table \type{\abc} title}{abc}
4 \stoptext
5
\@@kjtabletitle ->table \type {\abc
} title
\doif #1#2->\edef \!!stringa {#1
}\edef \!!stringb {#2}\ifx \!!stringa \!!str...
\dostructurecountercomponent ...\c!title }\v!none
{\setfalse \hasstructureco...
\docompletefloat ...c!title ={#4},\c!bookmark =][]
\globallet \previousfloatn...
<argument> ...{table \type {\abc } title}\nextbox
\else \docompletefloat {ta...
\secondoftwoarguments #1#2->#2
...
l.3 \placetable{table \type{\abc} title}{abc}
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