Dear Hans, Lucas, Wolfgang, Aditya
Now, I write a matrix using \startluacode by the helps of you.
Also, I can do some operations in matrices which reduced my typing job.
In this code, I have to give all the entries of a matrix as a table. It is good
to use in many cases.
I have one more question. If the given array is as the following and it works
well.
%%%%%%%%
\starttext
\startluacode
printMatrix = function (t)
context.startmatrix{left = "\\left(\\,", right = "\\,\\right)"}
for _, r in ipairs(t) do
for _, c in ipairs(r) do
context.NC(c)
end
context.NR()
end
context.stopmatrix()
end
\stopluacode
\startformula
\startluacode
local
mat={{"a_{11}","a_{12}","a_{13}"},{"a_{21}","a_{22}","a_{23}"},{"a_{31}","a_{32}","a_{33}"}}
printMatrix(mat)
\stopluacode
\stopformula
\stoptext
%%%%%%%%%%%%%
However, there might be a better way to do job using "for" iteration.
I tired to use "i, j" in several ways but it doesn't work.
function printMatrixA()
context.startmatrix{left = "\\left(\\,", right = "\\,\\right)"}
for i=1,3 do
for j=1, 3 do
context.NC("a_{ij}")
end
context.NR()
end
context.stopmatrix()
end
%%%%%%%%%%%%%%%
Is there a way to do such a job using "for" iteration?
Thank you for reading.
Best regards,
Dalyoung
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