Hans Hagen <pra...@wxs.nl> writes:
> indeed. this is what (sort of) happens in case of a plugged in renderer:
>
> \sqrt{#1} -> ...\mathstylehbox{#1}... -> ...\hbox{\stylecommand #1}...
>
> when #a = a \over b the style gets applied to the a only as \over
> creates two (pseudo) groups i.e. the \over isolates a and b
>
> > \sqrt{{k\over m}}\quad \sqrt{\displaystyle{k\over m}}
>
> would work ok
Ah, I understand. The extra-braces solution, \sqrt{{k\over m}}, is
simple and I can retain my \over habits.
-Sanjoy
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