Another bug.

@Hans: At least for user view point it's a bug. 
@Thangalin: thanks. A bigskip will solve me problems, but thanks.


\definemathmatrix[det]
[left={\left\lvert\,},right={\,\right\rvert}]


\starttext
Calculeu els determinants següents:

\startitemize[a,columns]

\item $\startdet[n=4]
\NC 1 \NC 1 \NC 1 \NC 1 \NR
\NC 1 \NC 2 \NC 3 \NC 4 \NR
\NC 1 \NC 3 \NC 6 \NC 10 \NR
\NC 1 \NC 4 \NC 10 \NC 20 \NR
\stopdet$

\item $\startdet[n=4]
\NC 1 \NC -2 \NC 0 \NC 1 \NR
\NC 1 \NC 1 \NC 0 \NC 2 \NR
\NC 0 \NC 3 \NC -2 \NC -1 \NR
\NC 1 \NC 1 \NC 1 \NC 3 \NR
\stopdet$

\item $\startdet[n=5]
\NC 1 \NC 2 \NC 3 \NC 4 \NC 5 \NR
\NC 2 \NC 3 \NC 4 \NC 5 \NC 1 \NR
\NC 3 \NC 4 \NC 5 \NC 1 \NC 2 \NR
\NC 4 \NC 5 \NC 1 \NC 2 \NC 3 \NR
\NC 5 \NC 1 \NC 2 \NC 3 \NC 4 \NR
\stopdet$

\item $\startdet[n=3]
\NC 1 \NC 2 \NC 3 \NR
\NC 1 \NC 4 \NC 9 \NR
\NC 1 \NC 8 \NC 27 \NR
\stopdet$

\stopitemize

Proveu, sense desenvolupar, que els determinants següents són nuls:

\startitemize[a]
\item $\startdet[n=3]
\NC -\sqrt{3} \NC 3 \NR
\NC 5 \NC -\sqrt{3}\cdot 5 \NR
\stopdet$

\item $\startdet[n=3]
\NC 2 \NC 1 \NC 3 \NR
\NC 1 \NC 0 \NC 1 \NR
\NC -3 \NC 2 \NC -1 \NR
\stopdet$

\stopitemize

\stoptext

Attachment: matrix2.pdf
Description: Adobe PDF document

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