On 1/14/2018 9:50 PM, Fabrice Couvreur wrote:
Hi Hans,
Your code runs perfectly, thanks. However, if I replace % with
\letterpercent, my code does not run
\ctxlua{print(string.format("\letterpercent g",Binomial(100,60,0.25)))}
because print prints to the console
Thank you
Fabrice
2018-01-14 13:58 GMT+01:00 Hans Hagen <pra...@wxs.nl
<mailto:pra...@wxs.nl>>:
On 1/14/2018 1:13 PM, Joseph Canedo wrote:
Hi Fabrice,
string.format behaves more or less as C printf. You probably
need to specify %.4g in 1st argument.
Hope this helps
Best
Joseph
*De : *Fabrice Couvreur <mailto:fabrice1.couvr...@gmail.com
<mailto:fabrice1.couvr...@gmail.com>>
*Envoyé le :*dimanche 14 janvier 2018 13:05
*À : *mailing list for ConTeXt users <mailto:ntg-context@ntg.nl
<mailto:ntg-context@ntg.nl>>
*Objet :*[NTG-context] Problem with string.format (Lua)
Hello,
I start with Lua and I try to display my result with 4 decimal
places without success.
Thank you
Fabrice
\startluacode
function Binomial(n,k,p)
if k > n then return nil end
if k > n/2 then k = n - k end
numer, denom = 1, 1
for i = 1, k do
numer = numer * ( n - i + 1 )
denom = denom * i
end
return (numer/denom) * p^k * (1-p)^(n-k)
end
\stopluacode
\starttext
\ctxlua{print(string.format("%g",Binomial(100,60,0.25)))}
\stoptext
the % should be \letterpercent
btw, use locals for numer and denom
you can also do this:
\startluacode
function document.Binomial(n,k,p)
if k > n then
return nil
end
if k > n/2 then
k = n - k
end
local numer, denom = 1, 1
for i=1,k do
numer = numer * ( n - i + 1 )
denom = denom * i
end
context("%0.5g",(numer/denom) * p^k * (1-p)^(n-k))
end
\stopluacode
\starttext
\ctxlua{document.Binomial(100,60,0.25)}
\stoptext
in general
context("format",....)
is a bit more powerful than using format
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