Hi,

Also good reading are the first sections in Roberto’s paper:

  http://www.inf.puc-rio.br/~roberto/docs/peg.pdf

> 
> In reality it just means that I was trying to add a new rule to solve
> the second part of the puzzle (hidden on the website until you solve
> the first part), which read something like
>    6: 3 | 3 6
> which would in theory be translated into something like
>    r6 = lpeg.V"r3" + lpeg.V"r3" * lpeg.V"r6",
> if PEGs worked the way I imagined they worked, that is. Apparently they don't 
> :)

Try this, blind guess: 

        r6 = lpeg.V"r3" * lpeg.V”r6” + lpeg.V"r3",

Best wishes,
Taco


Taco Hoekwater
Elvenkind BV




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