If you're really this concerned over accuracy, get/buy a Kill-A-Watt and
plug one into it, that will give you the actual W used by the device.
Nameplate or specification current ratings are generally higher than actual
usage.

Carl

 

From: Stefan Jafs [mailto:[email protected]] 
Sent: Tuesday, October 18, 2011 12:15 PM
To: NT System Admin Issues
Subject: Re: ( OT ) Convert mA to Watts

 

I guess the big unknown is the PF, I assumed 60% (based on Googeling), the
is a power supply, would it not be higher for a transformer load?

 

Stefan

On Tue, Oct 18, 2011 at 12:06 PM, Ben Scott <[email protected]> wrote:

On Tue, Oct 18, 2011 at 11:37 AM, Stefan Jafs <[email protected]> wrote:
> I'm, trying to figure out how much it cost to run some of our Medical Gas
> Alarm, current draw is 290 mA at 120 Volts, any ideas?
> This are my guess after some searches:
>

> .290 * 120 = 34.8 VA * 60% (PF) = 20.9 Watts I think that's correct ...

 Looks good to me, assuming your figure for the power factor is correct.

>... but how do I get to kWh?

 Run it for an hour.  ;-)

 20.9 watts is 0.0021 kilowatts.  Run it for an hour, and it's 0.0021
killowatt*hours.  Run it for half an hour, and it's 0.0011
killowatt*hours.  Run it for two hours, and it's 0.0042
killowatt*hours.

 Run it for about 476 hours, and it's 1 killowatt-hour.  (1 / 0.0021 =
476.190)

 Water makes a good analogy for electricity:

voltage = pressure (how hard is it pushing?)
amps = pipe diameter (how much can the wire/pipe carry?)
watts = gallons/hour (how much does it use to run?)
killowatt*hours = gallons (total amount of water/power)

 High pressure (voltage) in a small pipe (wire, amps) still yields a
high gallons/hour (watts).

 How long you run the hose (equipment), times the rate of flow
(watts) determines the amount of water (power, killowatt*hours) you
use.

-- Ben


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