On Wed, Aug 5, 2009 at 9:08 AM, Christopher
Bodnar<[email protected]> wrote:
> This does exactly what I want it to do, for the “{“ character:
> myRegExp.Pattern = "[^{]*\{([^}]*)\}"
> I want the exact same function, but for the double quote character.
First, an optimization. The above pattern, expanded with whitespace
for clarity, is:
[^{]* \{ ( [^}]* ) \}
Translated to English: Zero-or-more characters which are not an
opening-brace, followed by opening-brace, followed by a grouping of
zero-or-more characters which are not a closing-brace, followed by a
closing-brace.
I'm pretty sure you don't need that leading "zero-or-more characters
which are not an opening-brace" part. Regular expressions use partial
matching by default. So unless you anchor the pattern (start with ^
and/or end with $), there's no point. So here's a slightly simpler
version of your pattern:
\{ ( [^}]* ) \}
Translated to English: An opening-brace, followed by a grouping of
zero-or-more characters which are not a closing-brace, followed by a
closing-brace.
So to do the same for a double-quote:
" ( [^"] ) "
Back in VB syntax:
myRegExp.Pattern = """([^""])"""
This assumes quotes are always balanced and never nested. You can't
cope with that kind of complexity with standard regular expression
syntax.
-- Ben
~ Finally, powerful endpoint security that ISN'T a resource hog! ~
~ <http://www.sunbeltsoftware.com/Business/VIPRE-Enterprise/> ~
