os.path.split will only split the item after the last slash:
p = '/tmp/a/b/c/file.txt'
s.path.split( p )
('/tmp/a/b/c', 'file.txt')
whereas os.sep can be used in split() to split the whole thing:
p.split( os.sep )
['', 'tmp', 'a', 'b', 'c', 'file.txt']
On 16/05/12 7:48 PM, Howard Jones wrote:
os.path.split is the one I've always used. What's the advantage of os.sep?
H
------------------------------------------------------------------------
*From: * Frank Rueter <[email protected]>;
*To: * <[email protected]>;
*Subject: * Re: [Nuke-python] Re: Seeing inside a string, to replace a
file path
*Sent: * Tue, May 15, 2012 9:41:23 PM
check out os.path.split as well
On 16/05/12 8:51 AM, Nathan Rusch wrote:
There are a couple things you need to be aware of.
First, your string includes the ASCII control character \r. You
either need to escape your backslashes by doubling them up or use a
raw string:
"C:\\workFolder\\shots\\renderFolder"
# or
r"C:\workFolder\shots\renderFolder"
Now, the reason you're hitting a SyntaxError is because your split
string is an unescaped backslash, which makes Python think you're
trying to escape a single quote inside a single-quoted string and
then failing to complete the string with another single quote.
Escaping your backslash will work, but a safer bet is to use os.sep.
import os
r"C:\workFolder\shots\renderFolder".split(os.sep)
-Nathan
*From:* Noggy <javascript:return>
*Sent:* Tuesday, May 15, 2012 1:39 PM
*To:* [email protected] <javascript:return>
*Subject:* [Nuke-python] Re: Seeing inside a string, to replace a
file path
Thanks! Now I get it. Does split only work on a list? I am getting an
error trying to use split on a string. There's something about this
that isn't clicking for me.
wPath = "C:\workFolder\shots\renderFolder"
wPath.split('\')[:4]
SyntaxError: EOL while scanning string literal
------------------------------------------------------------------------
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