Sorry, slight typo in there. The append line in the nested loops should read:
idxs.append(i)
-Nathan
From: Nathan Rusch
Sent: Thursday, September 27, 2012 2:01 PM
To: Nuke Python discussion
Subject: Re: [Nuke-python] set node's output
Guessing a little here, since I’m not entirely clear what you’re trying to do,
but you probably want something like this:
def autoPremult():
try:
s = nuke.selectedNode()
except ValueError:
# No node selected
return
deps = s.dependent(nuke.INPUTS | nuke.HIDDEN_INPUTS)
idxs = []
for d in deps:
for i in range(d.inputs()):
if d.input(i) is s:
deps.append(i)
break
u = nuke.nodes.Unpremult()
u.setInput(0, s)
p = nuke.nodes.Premult()
p.setInput(0, u)
for d, i in zip(deps, idxs):
d.setInput(i, p)
-Nathan
From: Jason P Nguyen
Sent: Thursday, September 27, 2012 1:23 PM
To: Nuke Python discussion
Subject: [Nuke-python] set node's output
How do you set the output to connect to the bottom of the tree? I have this
but it kept branching out.
___________________
def AutoPremult():
s=nuke.selectedNode()
u=nuke.nodes.Unpremult()
u.setInput(0,s)
p=nuke.nodes.Premult()
p.setInput(0,u)
______________________
tried: p.setOutput(0) but still no luck.
Thanks.
J
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