Left/Right views for 'disparityL' and 'disparityR' should be identical
and in a perfect world the values between these channels should be the
inverse of each other in non occluded areas. With that you shouldn't
need to access the disparity values of a specific view.
Hope this helps.
Steve
On 19/12/13 14:00, Johannes Hezer wrote:
Nobody ?
Am 12/17/13 10:43 AM, schrieb Johannes Hezer:
Hey Nukers,
I do have to expose my stupidity.
I do not fully understand the concept behind the disparity channels
in nuke and how we should feed them from 3d.
We do have a shader that calculates the pixel distance between left
to right eye and from right to left eye.
Those get rendered in the according eyes.
So the disparityL.x channel contains "left to right" in the Left
image and "right to left" in the right image.
Now looking at nukes disparity setup I came to the conclusion (which
I am questioning a lot),
that the disparity needs to go into the channels disparityL.x (we
only have x difference) for the "left to right" stuff from the left
eye and in the disparityR.x I copied the "right to left" from the
right eye.
looking at that from the left view it all makes sense, so my next
conclusion was that the "right view" of the disparity channel (which
is the sum of disparityL and disparityR) does not need to have a
"right view" or should the right view be the same as the left view...
The reconverge node behaves as expected but I am not sure how the
disparity is supposed to look like from the right view.
So the questions are:
Does disparityL look the same through left and right eye ? Does it
need to have a right eye ? or can the right eye be black ?
Does disparityR look the same through left and right eye ? Does it
need to have a left eye ? or can the left eye be black ?
This all leads to the question is disparity "monoscopic" in nuke ?
with all that came another question if one can access the "other eye"
in the expression node ?
like disparityL.left.x (I have tried some combinations without success)
Or is there somewhere a page that explains all that ??
Thanks in advance for enlightening me.
Cheers
Johannes
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