Hi, > def d4(): > d = zeros([4, 1000], dtype=float) > for i in range(4): > xy = A[i] - B > d[i] = sqrt( sum(xy**2, axis=1) ) > return d > > Maybe there's another alternative to d4? > Thanks again,
I think this is the fastest you can get. Maybe it would be nicer to use the .sum() method instead of sum function, but that is just my personal opinion. I am curious how this compares to the matlab version. :) Johannes _______________________________________________ Numpy-discussion mailing list Numpy-discussion@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/numpy-discussion
