On 7/6/06, Tim Hochberg <[EMAIL PROTECTED]> wrote: > ... > So this is essentially turning a row vector into a column vector? Is > that right? > Being a definition, this is neither right nor wrong. It all depends on what you are using it for. If you want to distinguish row and column vectors, you have to use rank-2, but it is convenient to to think of rank-1 as an equivalent of either row or column and rank-0 as a 1x1 array. If you define transpose as a rank-2 only operation, but allow promotion of rank < 2 to rank 2, you end up with the rules of S+.
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