Here is the solution of a half of the problem: >>> a=array([1,2,3,0,40,50,60,0,7,8,9]) >>> 5+where(logical_and.accumulate(a[5:]!=0)) array([5, 6])
the rest is left as an exercise to the reader :-) Hint a[::-1] will reverse a. On 7/11/06, Mathew Yeates <[EMAIL PROTECTED]> wrote: > I can handle the following problem by iterating through some indices but > I'm looking for a more elegant solution. > > If I have a 1d array, I want to find a contiguous nonzero region about a > given index. For example, if a=[1,2,3,0,40,50,60,0,7,8,9] and we start > with the index of 5, then I want the indices 4,5,6 > > Any gurus out there? > > Mathew > > > > ------------------------------------------------------------------------- > Using Tomcat but need to do more? Need to support web services, security? > Get stuff done quickly with pre-integrated technology to make your job easier > Download IBM WebSphere Application Server v.1.0.1 based on Apache Geronimo > http://sel.as-us.falkag.net/sel?cmd=lnk&kid=120709&bid=263057&dat=121642 > _______________________________________________ > Numpy-discussion mailing list > Numpy-discussion@lists.sourceforge.net > https://lists.sourceforge.net/lists/listinfo/numpy-discussion > ------------------------------------------------------------------------- Using Tomcat but need to do more? Need to support web services, security? Get stuff done quickly with pre-integrated technology to make your job easier Download IBM WebSphere Application Server v.1.0.1 based on Apache Geronimo http://sel.as-us.falkag.net/sel?cmd=lnk&kid=120709&bid=263057&dat=121642 _______________________________________________ Numpy-discussion mailing list Numpy-discussion@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/numpy-discussion
