Sebastian Haase wrote: > Hi, > if I have a numpy array 'a' > and say: > a.dtype == numpy.float32 > > Is the result independent of a's byteorder ? > (That's what I would expect ! Just checking !) >
I think I misread the question and saw "==" as "=" But, the answer I gave should still help: the byteorder is a property of the data-type. There is no such thing as "a's" byteorder. Thus, numpy.float32 (which is actually an array-scalar and not a true data-type) is interepreted as a machine-byte-order IEEE floating-point data-type with 32 bits. Thus, the result will depend on whether or not a.dtype is machine-order or not. -Travis ------------------------------------------------------------------------- Take Surveys. Earn Cash. Influence the Future of IT Join SourceForge.net's Techsay panel and you'll get the chance to share your opinions on IT & business topics through brief surveys -- and earn cash http://www.techsay.com/default.php?page=join.php&p=sourceforge&CID=DEVDEV _______________________________________________ Numpy-discussion mailing list Numpy-discussion@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/numpy-discussion
