def rand(*shape):
"""
Return an array of the given dimensions which is initialized to
random numbers from a uniform distribution in the range [0,1).
rand(d0, d1, ..., dn) -> random values
or
rand((d0, d1, ..., dn)) -> random values
"""
if len(shape) == 0 or not hasattr(shape[0],'__getitem__'):
return numpy.random.rand(*shape)
else:
if len(shape) != 1:
raise TypeError('Argument should either be a tuple or an argument list')
else:
return numpy.random.rand (*shape[0])
On 8/22/06, David Grant <[EMAIL PROTECTED]> wrote:
On 8/21/06, Robert Kern < [EMAIL PROTECTED]> wrote:David Grant wrote:
> I was a bit surprised today to find that numpy.random.rand doesn't
> take in a tuple as input for the dimensions of the desired array. I am
> very used to using a tuple for zeros, ones. Also, wouldn't this mean
> that it would not be possible to add other non-keyword arguments to
> rand later?
Don't use rand(), then. Use random(). rand()'s sole purpose in life is to *not*
take a tuple. If you like, you can read the archives on the several (long)
discussions on this and why things are the way they are now. We finally achieved
something resembling consensus, so please let's not resurrect this argument.
Thanks everyone. My only question now is why there is random_sample and random. My guess is that one is there for compatibility with older releases and so I'm not bothered by it.
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